2. Black color in horse is dominant over chestnut color. If a homozygous black horse is mated to a homozygous chestnut horse, A. What is the genotype of the parents? B. How many offspring/s will be black color? C. How many offsprings will be chestnut color? What is the ratio of black to chestnut color ​

1. 2. Black color in horse is dominant over chestnut color. If a homozygous black horse is mated to a homozygous chestnut horse, A. What is the genotype of the parents? B. How many offspring/s will be black color? C. How many offsprings will be chestnut color? What is the ratio of black to chestnut color ​

Answer:

You can assign any type of letter to the characteristic. It is common to use the first letter of the dominant trait capitalized and the lower case for the recessive trait in this case.

Dominant is black hair (B)

Recessive trait is chestnut color (b).

Being homozygous means having 2 alleles of the same kind (so you could have dominant homozygous or recessive homozygous.. Being heterozygous means that you have one allele dominant and one recessive.

If the black horse is homozygous, the genotype is BB.

If the black horse is heterozygous, the genotype is Bb. Where Black is dominant and is expressed over the chestnut color.

2. 1. In horses, black coloring (B) is dominant, and chestnut coloring (b) is recessive. A homozygous black horse crosses with a chestnut horse. a. What percentage of offspring are expected to be chestnut? b. What percentage of offspring are expected to be heterozygous? ​

sorry po hindi konay alam

3. what are the main predators of chestnut munia?​

Answer:

The chestnut munia or black-headed munia (Lonchura atricapilla) is a small passerine. It was formerly considered conspecific with the closely related tricoloured munia, but is now widely recognized as a separate species.

Explanation:

sana makatulong

4. the athletics used the-(chestnut. torch) to light the caulron​

Answer:

The Olympic flame is a symbol used in the Olympic movement. It is also a symbol of continuity between ancient and modern games. ... This ceremony starts the Olympic torch relay, which formally ends with the lighting of the Olympic cauldron during the opening ceremony of the Olympic Games.

5. Problem 2 Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?​

Question:

Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?

Solution:

Let xx be the amount Peter picked. Then Mary and Lucy picked 2x2x and x+2x+2, respectively. So x+2x+x+2=26x+2x+x+2=26

4x=244x=24

x=6x=6

Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.

#CARRYONLEARNING

Question:

Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?

Solution:

Let xx be the amount Peter picked. Then Mary and Lucy picked 2x2x and x+2x+2, respectively. So x+2x+x+2=26x+2x+x+2=26

4x=244x=24

x=6x=6

Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.

#CARRYONLEARNING

6. 2. The allele for a white allele coat color in horses is W while the allele for chestnut is C. The heterozygous phenotype is known as roan. If two roans horse were crossed, what is the probability that a) They would have a chestnut foal (baby horse)? b) They would have a white foal (baby horse)? c) They would have a roan foal (baby horse) ? pahelp wag na sagutin kung di alam sayang 30points matino sana

answers:A 25%B 36%C 50%explantion:

7. 5. Mary, Peter and Lucy were picking chestnuts, Mary picked twice as much chestnuts thanPeter, Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg ofchestnuts. How many kilograms did each of them pick?​

Mary has 12 chestnuts
Lucy has 8 chestnuts
Peter has 6 chestnuts

Solution:
Mary picked TWICE as much chestnuts than Peter...
6x2=12

Lucy picked 2 kg more than Peter..
6+2=8

6+8+12=26 kg

8. Autumn moonlight-dige silentlyinto the chestnut.Matsu. Basho what idea is expressed in each poem ?​

Answer:

(“Autumn”). ... He describes “autumn moonlight” as a crow perched upon a branch empty of leaves.

9. Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick the amount Peter picked the amount Mary picked the amount Lucy picked

Answer:

the amount Peter picked

Answer:

they each picked 28 kg.

Step-by-step explanation:

that is all i know

10. butterduckblockbusterluckyberrywellnessberryclustermenbookshelveseggplantrustycutcoconutumbrelladentistchestnutearthread the word in the box.then color the word red if it two-sylable with short /e/​

Answer:

red color:

butter

blockbuster

berry

wellness

cluster

men

chestnut

earth

Explanation:

all the word merong e

11. The children collected the chestnuts that (fell/ had fallen) from the tree.​

The children collected the chestnuts that had fallen from the tree.

12. is chestnut munia a endangered species or an special bird?

Answer:

baby ko si kulot inaalis niya aking lungkot

Answer:

special bird

Explanation:

13. Horses can be cremello (a light cream color), chestnut (a brownish color), or palomino (a golden color with white in the horse’s tail and mane). Of these phenotypes, only palominos never breed true. cremello palomino h 1/2 cremello 1/2 palomino chestnut palomino h 1/2 chestnut 1/2 palomino 1/4 chestnut palomino palomino h 1/2 palomino 1/4 cremello (a) From the results given above, determine the mode of inheritance by assigning gene symbols and indicating which genotypes yield which phenotypes.

Answer:

a) The mode of inheritance in this situation is Incomplete Dominance, a form of intermediate inheritance in which one allele for a specific trait is not completely expressed over its paired allele. This results in a third phenotype in which the expressed physical trait is a combination of the phenotypes of both alleles.

    Cremello = CC (dominant purebred)

    Palomino = Cc (never breed true)

    Chestnut = cc (recessive purebred)

b) In the first case (Cremello Palomino Horse), the progenies are 1/2 Cremello or 2 Cremello and 1/2 Palomino chestnut horses. The genotypes of these phenotypes are: 2 CC, and 2Cc. From the genetic cross of CC x Cc also.

Next, for the chestnut palomino horse, the offspring are 1/2 chestnut and 1/2 palomino. The genotypes of these phenotypes are: 2cc, and 2Cc. From the genetic cross of cc x Cc.

Lastly, for the Palomino Palomino, the outcomes are 1/4 chestnut palomino, 1/2 palomino, and 1/4 cremello. The genotypes of the these phenotypes are: 1cc, 2 Cc, and 1 CC. From the genetic cross of Cc x Cc.

14. a chestnut brown horse mates with a creamy white one and all offspring are palominos.Coat color among horses exhibit which of the following?a. Incomplete dominanceb. sex influenced traitc. multiple allelesd. codominance​

Answer:

a. in complete dominance

Explanation:

Sana makatulong

15. Is chestnut munia a endangered species or an special bird? and why?

Answer:

the following is not right for the person you have read by a few cheks in the amazing molecules is an instrumental beats with me and my mom said you had a dream about it important things in writing to

Answer:

Yes

Because i dont know the answer

Explanation:

hope it works

16. matatagpuan ito sa rehiyon ng gitnang latitud o temperate zone kung saan makikita ang mga punong Oak beech chestnut, at iba pa​

Answer:

Vegetation ng Asya

Explanation:

Tama po ba

17. Mary , Peter and Lucy were picking chestnuts, Mary picked twice as much chestnuts thanPeter, Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg ofchestnuts. How many kilograms did each of them pick?​

Answer:

12 kg each of them pick the chestnuts

18. 2Offspring of parents #250% palomino25% chestnut brown25% creamy white in science class​

Answer:

we are going to be in the office tomorrow and will be back in the office on Monday and Tuesday and Wednesday

Explanation:

yes I will be there at kapwa mamayan dapat gawin I am so I can get the kids to bed to be easier e

19. Write "yes” if the given problem is an example of routine and "no" if it is not. Write your answer on the blank provided before each number. 1.there are 35 cacao nuts in every lunchbox.how many cacao nuts are there in the 5 lunchboxes? 2.there are 35 chestnuts in every jar. how many chestnuts are there in 7 jars? 3. Christ bought three boxes of bibingka with 8 slices each and he is going to have six visitors. how many slices can each visitors have? salamat sa sasagot

Answer:

1)yes -7

2)yes -5

3)yes-4

20. the children collected the chestnuts that (fall) from the tree​

Answer:

Fell po ang sagot

The children collected the chestnuts fell from the tree

21. The children collect the chestnut that (fall) from the tree

Answer:

nasaan Yung direction o question mo??

Explanation:

para masagutan tnx

BTW pabrainliest please

the children collect the chestnut that (fell) from the tree

fell - is an past tense

hope this helps

#carry on learning

#stay safe

22. Write "yes” if the given problem is an example of routine and "no" if it isnot. Write your answer on the blank provided before each number.1.there are 35 cacao nuts in every lunchbox.how many cacao nuts are there in the 5 lunchboxes?2.there are 35 chestnuts in every jar. how many chestnuts are there in 7 jars?3. Christ bought three boxes of bibingka with 8 slices each and he is going to have six visitors. how many slices can each visitors have?​

Answer:

1.7

2.5

3.17

why? 35 divide by 5 = 7

35 dived by 7 = 5

3,8,6 add =17

23. Rr - pinkRR- redWW- whiteBB- blackBBCC- chestnutbbCc- palominocc- albinoSS - straightCC- curlySC- wavy​

Answer:

pink and red white and black albino and straight,

curly wavy

Explanation:

yun lang po ang Alam ko lol paki brainlist naman po plsss I need points if I wrong

24. 3. The children collected the chestnuts that (fall)from the tree4. She (ridea horse before that day5. He drivethe car fast when his mother called​

i think the answer is 4 im not really quite sure

25. A. Cross the following monohybrid problems using Punnet square andwrite your answer right after the problems.1. The Palomino horse is a hybrid exhibiting a golden color with lighter mane and tail. A pair of codominant allelles D1 and D2 is known to be involved in the inheritance of these coat colors. D1D1 horse are chestnut colored while D2D2 are cremello or almost white. What are the chances of producing Palomino horses in the following crosses:a. Palomino x Chestnut b. Chestnut x Cremelloplease answer guys, i really need help...thanks

Answer:

a. Palomino (D1D2) x Chestnut (D1D1) will have a 50 % chance of producing palomino horses

b. Chestnut (D1D1) x Cremello (D2D2) will have 100% chance of producing Palomino horses.

NOTE: Please see attached file for the punnet square of the above answers

Explanation:

Monohybrid is a kind of cross that will show the inheritance of one trait. To understand the monohybrid cross, it is important to understand several terms related to genetics. Each trait is represented by pair of alleles. Alleles are variant forms of genes. A dominant allele is a variant that is visible or will show in the characteristics of the organism and it is usually represented by a capital letter. A recessive allele on the other hand is the variant that is will be hidden in case it is paired with a dominant allele. This will just show if it is paired with another recessive trait. Let us take for example the pea color - it can either be yellow (G) or green (g). When the gene is GG or Gg, it will result in yellow peas while when the gene is gg, it will result in green peas. The combination of this allele is a called genotype. So in the example of pea color, possible genotypes are GG, Gg, gg. Expressed traits are referred to as phenotypes. In the example, green and yellow pea colors are the possible phenotypes.  GG and gg are considered homozygous genotypes, wherein the gene contains the same alleles - either all dominant or all recessive. Gg, on the other hand, is a heterozygous genotype.

In the given situation on the color of the horse, there are two alleles involved - allele for chestnut (D1) and allele for cremello (D2). The chestnut-colored horse will have a genotype of D1D1, cremello will have D2D2, while the Palomino horse will have  D1D2 genotype. However, this is another kind of inheritance, namely the codominance.  In this type of inheritance, there is no recessive trait or allele. Thus, if we have a heterozygous genotype, both traits will be expressed. Like Palomino horse is a hybrid or has a heterozygous genotype and since the alleles are codominant, both will be expressed in the palomino's horse phenotype. Specifically, it has a golden color with a lighter mane and tail.

To predict and get possibilities of offspring, a Punnet square may be used. It is a simple graphical representation to show possible combinations of alleles in the offspring's genotype.

#BRAINLY FAST

26. Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?please pasagot po now na.​

Answer:

Peter 6, Mary 12, Lucy 8, kg respectively.

Step-by-step explanation:

Let x be the amount Peter picked. Then Mary and Lucy picked 2x and x + 2, respectively. So:

[tex]x + 2x + x + 2 = 26[/tex]

[tex]4x = 24[/tex]

[tex]x = 6[/tex]

Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg.

#CarryOnLearning

Answer:

Peter = 6 kg, Mary = 12 kg, Lucy = 8 kg

Step-by-step explanation:

Let x be the number of chestnuts picked by Peter.

Then, Peter = x, Mary = 2x, Lucy = x + 2.

Since they picked 26 kg of chestnuts altogether, we have to add the values.

So, (x) + (2x) + (x + 2) = 26

4x + 2 = 26

4x = 24

x = 24/4 = 6

Plugging back the values of each person for x = 6.

Then, Peter = 6 kg, Mary = 2(6) = 12 kg, Lucy = (6) + 2 = 8 kg.

Please mark me brainliest if it helps!

~~DeanGD20

#CarryOnLearning

27. The allele for a white allele coat color in horses is W while the allele for chestnut is C. The heterozygous phenotype is known as roan. If two roans horse were crossed, what is the probability that: a) They would have a chestnut foal (baby horse)? b) They would have a white foal (baby horse)? c) They would have a roan foal (baby horse) ?

Answer:B

Explanation:

28. The children collected the chestnuts that ______ (fall) from the tree. A.have fallen B.had fall C.had fallen

Answer:

A- Have fallen

Explanation:

i hope na makatulong

29. NONSENSE ANSWER WILL BE AUTOMATICALLY REPORTED. SHOW YOUR SOLUTIONS. BRAINLIEST PO ANG MAY TAMANG SAGOT. Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?​

Answer:

Let the mass of chestnuts Lucy picked be called L. Since Mary picked twice as much chestnuts as Peter, M = 2P. Since Lucy picked 2kg more than Peter, L = P+2.

Step-by-step explanation:

hope it helps

30. 2. The allele for a white allele coat color in horses is W while the allele for chestnut is C. The heterozygous phenotype is known as roan. If two roans horse were crossed, what is the probability that a) They would have a chestnut foal (baby horse)? b) They would have a white foal (baby horse)? c) They would have a roan foal (baby horse) ? matino sana

Answer:

B.They would have a white foal (baby horse)?

Explanation:

correct me if im wrong